For alkali metals, threshold frequencies lie | vedclass

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Question

(A) The threshold frequency $( 
u_0)$ is the minimum frequency of incident radiation required to eject photoelectrons from a metal surface.Alkali met

Vedclass · Accepted Answer

Visible region

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(A) The threshold frequency $( 
u_0)$ is the minimum frequency of incident radiation required to eject photoelectrons from a metal surface.Alkali metals (such as Lithium, Sodium, Potassium, etc.) have very low work functions $( \Phi_0 = h 
u_0)$.Because their work functions are low, the energy required to eject electrons is small, which corresponds to a lower threshold frequency.This threshold frequency for alkali metals typically falls within the visible region of the electromagnetic spectrum.Therefore, visible light is sufficient to cause the photoelectric effect in alkali metals.

For alkali metals, threshold frequencies lie in which region?

Similar Questions

Which of the following phenomena is not explained by the wave nature of light?
$(A)$ Reflection
$(B)$ Diffraction
$(C)$ Photoelectric effect
$(D)$ Interference
$(E)$ Polarization
Choose the most appropriate answer from the options given below:

$A$ photoelectric cell is illuminated by a point source of light $1 \ m$ away. When the source is shifted to $2 \ m$,then:

Threshold frequency for a metal is $10^{15} \ Hz$. Light of $\lambda = 4000 \ \mathring{A}$ falls on its surface. Which of the following statements is correct?

When the intensity of incident light increases:

Define the work function of a metal and write its unit.

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